Note on how ti find finding circumference?

Circumference of a circle:

In this section let me help you on finding circumference finding circumference. Keep reading if you still have any problems or doubts in learning do leave your comments.

The circumference of a circle is the length around it. The circumference of a circle can be calculated from its diameter using the formula:

Or, substituting the radius for the diameter:

This could also help us on solving equations by factoring

where r is the radius and d is the diameter of the circle, and π (the Greek letter pi) is defined as the ratio of the circumference of the circle to its diameter (the numerical value of pi is 3.141 592 653 589 793...)

Algebraic Formulas

Introduction to algebraic formula:

In this Lesson we are going to learn about algebraic formula. Many algebraic formulas we are using in math. Algebraic formula using two or three different variables. In this lesson we'll learn more. In this lesson covers algebraic formula reference sheet has the following algebraic formulas with operations like addition, subtraction, multiplication, and division and also has some properties like associative, commutative, and distributive properties....

List of Geometry Algebraic Formula:

1. Slope: If two points, (x₁, y₁) and (x₂, y₂) are given, the slope is equal to y₂ – y₁ / x₂ – x₁
2. Standard form of an equation: Ax + By = C
3. Slope-intercept form of an equation: y = mx + b This could also help us on chemical equation calculator
4. Point-slope form of an equation: y – y₁ = m(x – x₁), where (x₁, y₁) is a point on the line, and m is the slope.
5. Value of a determinant: | a b | = ad – bc
6. Cramer’s rule: ax + by = e
7. Distance formula: d = the square root of (x₂ – x₁)² + (y₂ – y₁)²

Note on distributive property calculator

In this article let me help you on distributive property calculator. Keep reading let me help you with the following example.

let us show as, a ( b-c ) = ab - ac, where as a, b, c are real numbers

Solution: a (b-c) = a (b+(-c))

= a.b+a.(-c) (using distributive property)

= ab+(-ac)

= ab - ac

2) Simplify, 5(11+12)

Solution: Given, 5(11+12)

Using distributive property for real number,

5(11+12) = 5*11 + 5*12

= 55 + 60

= 115. This could also help us on answers to math problems free

3) Obtain 17 * 99 using distributive law

Solution: We know, 99 = 100 -1

So, 17 * 99 = 17*(100-1)

= 17*100 - 17*1

= 1700 - 17

= 1683

3) (-5) *(-196) = (-5) ( -100+(-96))

= (-5)*(-100) + (-5)(-96)

= 500 +480

= 980

Questions to solve:

1) 18 * 102

2) 13 * 28

Math homework help

Introduction about mathematics homework help tutorial
In this article you will get help on math homework help problems with the help of the tutor through online. Online help will be easier for the students to their homework problems in mathematics. Students can get instant help from any part of the world. This tutorial also include word problems. Below are some of the mathematics homework problems.

Help on Homework Problem in Mathematics:

1. Add 324 + 261

Tutor Solution
3 2 4 Add the ones digit 4 + 1 = 5
2 7 1 + Add tens digit 2 + 7 = 9
---------- Add hundred’s digit 3+ 2 = 5
5 9 5
---------- This could also help us on online algebra homework

Statistics Home-work Help Online Tutor

Introduction to Statistics Home-work Help Online Tutor

In this article let me help you on statistics home-work help online. Online tutors are the individuals who will help the scholars in studies and report the new additional skills by using a step-by-step method. Online tutors are explaining the issues to the scholars. So the scholars can clear the doubts within a minute. Statistics is the most important idea in maths. Statistics is the appropriate science. Now let me show you a example on statistics. This will help you on understanding better.

Example:
Find out the Median for the following sequence. 24,28,32,37,42. This could also help us on trigonometry homework
Solution:

First sort the above numbers. They get 24,28,32,37,42.

The middle element is 32.

Therefore median=32.

Help on Statistics Problems Solved

In this article let me help you on statistics problems solved. Since we had studied enough on statistics let me help you with the sample problems.

Following is the sample problem on statistics:

Problem 1

For boys, the average number of absences in the first grade is 15 with a standard deviation of 7; for girls, the average number of absences is 10 with a standard deviation of 6.

sample?

(A) 0.025
(B) 0.035
(C) 0.045
(D) 0.055
(E) None of the above
Solution

The correct answer is B. The solution involves four steps. This could also help us on statistics answers online
* Find the mean difference (male absences minus female absences) in the population.
μd = μ1 - μ2 = 15 - 10 = 5

* Find the standard deviation of the difference.
σd = sqrt( σ12 / n1 + σ22 / n2 )
σd = sqrt(72/100 + 62/50) = sqrt(49/100 + 36/50) = sqrt(0.49 + .72) = sqrt(1.21) = 1.1

* Find the z-score that produced when boys have three more days of absences than girls. When boys have three more days of absences, the number of male absences minus female absences is three. And the associated z-score is
z = (x - μ)/σ = (3 - 5)/1.1 = -2/1.1 = -1.818


Therefore, the probability that the difference between samples will be no more than 3 days is 0.035.

square root of 18

Introduction to what is the square root of 18:

In mathematics, we use a math square root symbol, which is known as radical. The mathematical symbol of radical is (√). Rubicund is referred to a number which is present inside the root (i.e., here x is referred as rubicund). Let us discuss about the topic “what is the square root of 18”, some calculation to find what is the square root of √18 .

What is the Square Root of 18? Define Methods:

What is the square root of 18 involves in determining the value of [sqrt (18)] in two methods,


* In long division method, we divide the square root value in long division method which has slight variation from normal division.

* Average finding method solves square root of 18 by taking the nearest root value of 18, then find average and square it. Finally squaring the average we obtained. Which the above two methods are explained below with calculations. This could also help us on linear algebra toolkit